Talk:Problemas y ejercicios de mecánica/@comment-25438755-20140922152342

El vector v se define como dr/dt por lo tanto

v=s'·uxv + s·(uxv)'= -bae^(-bt)·{cos(wt), sin(wt), 0}+ ae^(-bt)·{wsin(wt), -wcos(wt), 0} =

=s(-b·uxv+{wsin(wt), -wcos(wt), 0})= s{-bcos(wt)+wsin(wt), -bsin(wt)-wcos(wt), 0}

A su vez a= dv/dt => a= s'·{-bcos(wt)+wsin(wt), -bsin(wt)-wcos(wt), 0} + s·{-bcos(wt)+wsin(wt), -bsin(wt)-wcos(wt), 0}'= ... = ae^(-bt)·[-b{-bcos(wt)+wsin(wt), -bsin(wt)-wcos(wt), 0} + w{-bsin(wt)- wcos(wt), bcos(wt) - wsin(wt), 0}]